A == B ?

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 49403    Accepted Submission(s): 7593

Problem Description

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

 

 

Input

each test case contains two numbers A and B.

 

 

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

 

 

Sample Input

1 2

2 2

3 3

4 3

 

 

Sample Output

NO

YES YES NO

 

 

Author

8600 && xhd

 

 

Source

 

 

此题解法：分整数和小数两部分来比较即可！！但要注意的事情还是比较多的

需要考虑：

+0.000    0.00

YES

+0.00 -0.00

YES

+0001.00 1

YES

+000.0000100  .00001

YES

代码如下：

1 #include
      
        2 #include
       
         3 #define MAX 20000 4 char a[MAX],b[MAX]; 5 char ra[MAX],apoint[MAX], 6      rb[MAX],bpoint[MAX]; 7 void func(char *a,char *ra,char *apoint) 8 { 9     int i=0,k=0;10     bool flag=true;11     int len=strlen(a);12     if(*a=='+')i++;13     else if(a[0]=='-')14     {15         ra[k++]='-' ;16         i=k;17     }18     for( ; a[i]=='0'&&i
        
         =i;j--);27    28    for(k=0 ; i<=j ; i++)29     {30         apoint[k++]=a[i];31     }32 }33 34 int main( void )35 {36     while(scanf("%s%s",a,b)!=EOF)37     {38         memset(ra,'\0',sizeof ra);39         memset(apoint,'\0',sizeof apoint);40         memset(rb,'\0',sizeof rb);41         memset(bpoint,'\0',sizeof bpoint);42         func(a,ra,apoint);43         func(b,rb,bpoint);44       if(strcmp(ra,rb)==0&&strcmp(apoint,bpoint)==0)45           puts("YES");46       else if((*rb=='-'&&*(rb+1)=='\0')&&strcmp(apoint,bpoint)==0)47           puts("YES");48      else if(*ra=='-'&&*(ra+1)=='\0'&&strcmp(apoint,bpoint)==0)49                puts("YES");50      else51           puts("NO");52     }53     return 0;54 }